Cuts right part of a string starting from certain occurrence of a separator until end of string.
Like CutString3 but it will return all items starting i to the end.
Edit 2025-08-07: Removing separator if found at start, for some reason we are seeing this case.
Edit 2025-07-28: Adding ability to remove separator from end if found as blank.
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Linkedin LoginCutFrom, StartFrom_ID_TillEnd, Optional Sepa = "|"
Print CutString7("some|1|have|to|say|happy|new|year|to someone", 3, "|")
"to|say|happy|new|year|to someone"
"to|say|happy|new|year|to someone"
Views 297
Downloads 121
CodeID
DB ID

ANmarAmdeen
777
Revisions
v3.0
Thursday
August
7
2025
Codes Required 0

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